- A triangle of sides a,b,c
- A square of side a
- a perpendicular bisector
- A square inside a circle
- A regular hexagon inside a circle
- An (equilateral) triangle inside a circle
- Starting at one end of the length of a, with the compass stretch out to the lenght of b, mark an arch. do a similar process for the length of a at the other end of a.
- The intersection of the two arcs will be the third point in the abc triangle.
- With the compass get the length of AB
- At both ends of AB, using the compass and keeping the length of AB, draw a large enough arc so that there is two intersection
- Align the ruler with the two intersection and draw a line (the resulting line is the perpendicular bisector)
This construction is quite similar to the previous one. In a circle with diameter AB
- draw a perpendicular bisector like before and long enough that the bisector instersects the circle on both end
- Connect the 4 points on the circle which yields a square in the circle
- Was there any practical application, back then, of constructing with just a ruler and a compass?
Complexity: 4
Interesting: 5
Quality: 8
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